Gradle evaluates using empty build file

Help/Discuss
1

I am getting below error when trying to run grdle tasks command

Evaluating project ‘:Project1’ using empty build file.
Evaluating project ‘:Project2’ using empty build file.
I have multiproject build

Main
|–Root
|----Project1
|----Project2
|–build
|----settings.gradle
|----build.gradle
|----sub-project.gradle

and below is my settings.gradle

File modulesDir = new File("${rootProject.projectDir}/…/Root").canonicalFile
modulesDir.eachFile {
include it.name
}
rootProject.children.each {
it.projectDir = new File(modulesDir, it.name)
it.buildFileName = ‘./sub-project.gradle’
}
this line is not working

it.buildFileName = './sub-project.gradle’
the sub-project.gradle is not getting assigned to sub project.

whats the problem? How can one assign actual build file to project?

2

buildFileName is evaluated relatively to its project directory, using its project’s method file.

So, your code

it.buildFileName = './sub-project.gradle'

should be

it.buildFileName = '../sub-project.gradle'

The complete sample is available at my repo.

or define at build.gradle

subprojects {
    apply from: 'sub-project.gradle'
}
3

I have made the changes as per your suggestion, but the problem is still there.

4

Did you see my sample? It seems any one doesn’t click the link.

The sample works well.

5

This works well! now I have another problem Project2 has dependency on Project1 so when I execute gradle build it fails. How to add this dependency?

6

Add project dependency declaration in your sub-project.gradle.

for example…

ext {
  // if this project is Project2 then this value becomes true. If Project1, it's false.
  dependence = project.name != 'Project1'
}
dependencies {
  // some your dependencies

  // If this project is Project2 then depend on Project1
  if(dependence) {
    compile project.rootProject.project(':Project1')
  }
}

The sample project, which I mentioned before, is currently adjust your requirement. And it works well.

1 Like
7

Thank you very much!