Problem with Resources

Old Forum Archive
1

Hi there

I’m developing a java application and I’m using gradle as my default build system. I love it so far :slight_smile: I only have one problem: I read an config file like this in my java code:

URL url = Main.class.getResource("/configuration/Config.xml");
  File file = new File(url.getFile());

And here’s my project structure:

|-- src
|
  |-- main
|
       |-- java
|
       |
  \-- ch.example.bla
|
       |
       |-- Main.java
|
       |-- resources
|
            \-- Config.xml
\-- build.gradle

And here’s my Gradle build file:

apply plugin: 'java'
  repositories {
 mavenCentral()
}
  dependencies {
 compile group: 'commons-collections', name: 'commons-collections', version: '3.2'
 testCompile 'junit:junit:4.11'
}
  sourceCompatibility=System.properties['java.specification.version']
version = '1.0'
  compileJava {
 options.compilerArgs.add '-XDignore.symbol.file'
    options.fork = true
    options.forkOptions.executable = "javac" // assumes that javac is on PATH
    options.compilerArgs << "-XDignore.symbol.file"
}
  jar {
 manifest {
  attributes 'Implementation-Title': 'ResourceTest',
       'Implementation-Version': version,
       'Main-Class': 'ch.example.bla.Main'
 }
}

When I run the program via eclipse, then it works without a problem. But when I generate the jar-file with the command “gradle build” then i get an exception. What am I doing wrong?

Kind regards Marc

2

Please always provide the full error message/stack trace.

3

Oh sorry. Here’s my error message, when I try to execute the jar-file via console (with the command: “java -jar ResourceTest.jar”):

java.io.FileNotFoundException: D:\Tutorial\Spring\eclipse\workspace\ResourceTest\build\libs\file:\D:\Tutorial\Spring\eclipse\workspace\ResourceTest\build\libs\ResourceTest-1.0.jar!\configuration\Config.xml (Die Syntax für den Dateinamen, Verzeichnisnamen oder die Datenträgerbezeichnung ist falsch)
        at java.io.FileInputStream.open(Native Method)
        at java.io.FileInputStream.<init>(Unknown Source)
        at java.io.FileInputStream.<init>(Unknown Source)
        at sun.net.www.protocol.file.FileURLConnection.connect(Unknown Source)
        at sun.net.www.protocol.file.FileURLConnection.getInputStream(Unknown Source)
        at com.sun.org.apache.xerces.internal.impl.XMLEntityManager.setupCurrentEntity(Unknown Source)
        at com.sun.org.apache.xerces.internal.impl.XMLVersionDetector.determineDocVersion(Unknown Source)
        at com.sun.org.apache.xerces.internal.parsers.XML11Configuration.parse(Unknown Source)
        at com.sun.org.apache.xerces.internal.parsers.XML11Configuration.parse(Unknown Source)
        at com.sun.org.apache.xerces.internal.parsers.XMLParser.parse(Unknown Source)
        at com.sun.org.apache.xerces.internal.parsers.DOMParser.parse(Unknown Source)
        at com.sun.org.apache.xerces.internal.jaxp.DocumentBuilderImpl.parse(Unknown Source)
        at javax.xml.parsers.DocumentBuilder.parse(Unknown Source)
        at ch.example.bla.Main.main(Main.java:38)

I think I didn’t specify it before. But my gradle build runs without a problem. It generates the reports and the jar-file. I get the exception, when I run the jar file…

4

I posted the full error message in a reply. Thanks :slight_smile:

5

Looks like your code to turn the resource into a file doesn’t work when the resource is contained in a Jar (which it probably doesn’t when run from Eclipse). If all you need is to read the resource, use the ‘getResourceAsStream()’ method.